**Vedic Maths Addition Tricks **

Addition is the process of calculating the total of two or more whole numbers. It is one of the four basic operations of arithmetic, the other three are subtraction, multiplication and division.

Addition has two important properties. It is commutative which means the order does not matter, and another is associative, it means, when one adds more than two numbers, the order in which addition is performed does not matter.

**Commutative**:

It doesn’t matter whether you add 6 to 8 or add 8 to 6, the answer will remain the same no matter what order the terms are in. e.g.

5 + 9 = 9 + 5 = 14

14 + 6 = 6 + 14 = 20

**Associative**:

It states that if you have a number of additions to perform it doesn’t matter which order you do them in. e.g.:

(7 + 3) + 5 = 5 + (3 +7) = 15

17 = (9 + 4) + 4 = 4 + (4 + 9)

In vedic maths addition is one of the most basic operations. It has also certain ways of adding numbers, which is different from traditional methods.

For doing effective additions in vedic maths you need to memorize some calculations. Though it is obviously impossible to memorise all possible calculations,

But …..

certain amount of memorisation is essential, which is the minimum requirement that will vastly improve the efficiency of many calculations.

**Some Essential Memorization**

All sums upto 10:

2 + 7 = ….

6 + 4 = ….

8 + 2 = ….

9 + 1 = ….

etc…

All compositions of 10:

4 + …. = 10

8 + …. = 10

3 + …. = 10

6 + …. = 10

etc….

Simply memorising the above not only lets you calculate any sum but also saves a lot of time to also memorise the sum of all pairs

All single digit sums:

6 + 7 = ….

8 + 4 = ….

6 + 9 = ….

9 + 8 = ….

etc ….

In vedic maths while adding a two digit number we should see whether the unit digit added up to give 10.

For example, 17 + 3 = 20 , here the unit digit or one’s place add up to give 10 , so we round number 17 to nearest tens that is 20.

**By Using Base Method **

It is easier to add numbers which are closer to 10s multiple. For example,

7, 8, 9 are closer to 10 or 21, 22, 23 are closer to 20 and so on.

Suppose, we have to add 38 and 97.

Step 1: Add 40 and 100 which are closer to numbers (38 – 40, 97 – 100). It gives 40 + 100 = 130

Step 2: Add the differences, 2 + 3 = 5

(40 – 38 = 2, 100 – 97 = 3)

Step 3: Subtract results obtained from step 2 and step 1, that is 130 – 2 = 125

》Answer is 125

**By Using Balancing Rule**

Addition using balancing rules method helps you to forget the carry forward system, which makes you confused most of the time.

Traditional methods force you to use carrying systems.

Here’s how we apply this method,

**Example 1: **

3956 + 2875

3 9 5 6

+2 8 7 5

______________

5 | 17 | 12 | 11

**6** (5+1) **8** (7+1) **3** (2+1) **1**

Starting from left drop 1 and carry another 1 to next number 12 (12+1)=13, drop 3 and carry 1 to again next number 17 (17+1)=18, drop 8 and carry 1 to next number 5 (5+1)=7

》 Answer is 7831

**Example 2: **

9876 + 8765 + 7654

9 8 7 6

8 7 6 5

7 6 5 4

________________

24 | 21 | 18 | 15

**26** (4+2) **2** (1+1) **9** (8+1) **5**

Apply the same Balancing rule.

》 Answer is 26295

**Example 3:**

9989 + 8876 + 7568 + 8567

9 9 8 9

8 8 7 6

7 5 6 8

8 5 6 7

_______________

32 | 27 | 27 | 30

**35** (32+3) **0** (27+3) **0** (27+3) **0**

Apply the same Balancing rule.

**》 **Answer is 35000

**By Using Split Method**

It is a very effective method. Calculate in your mind and say the answer quickly within 2 sec. But it requires regular practice. More you practice, the less response time.

**Example 1: **

456 + 76

4 5 6

7 6

____________

400 + 120 + 12 = 532

First 4 is in hundreds place so take 400, 5 + 7 = 12 are in 10s place so add 120, 6 + 6 = 12 is in one’s place so add 12 as it is.

》 Answer is 532

Though this one is a very small number, by practicing the same method you can solve any big problem.

Let’s take one more example with big numbers.

**Example 2:**

5678 + 647 + 69

5 6 7 8

6 4 7

6 9

___________

5000 (5 and 1000s place) + 1200 (6+6 and 100 place) + 170 (7+4+6 and tens place) + 24 (ones place)

》 Answer is 6394

**Example 3:**

9867 + 8564 + 6638 + 4732

9 8 6 7

8 5 6 4

6 6 3 8

4 7 3 2

___________

27000 + 2600 + 180 + 21 = 29801

{ 27000 (9+8+6+4 and 1000s place) + 2600 (8+5+6+7 and 100s place) + 180 (6+6+3+3 and 10s place) + 21 (7+4+8+2 and one place) }

》Answer is 29801

**By Using Breaking Place Value**

**Example: **

16 + 87

= 10 + 6 + 80 + 7 = 10 + 80 + 6 + 7 = 90 + 13 = 103

72 + 96 = (70 + 2) + (90 + 6) = (70 + 90) + (2 + 6) = 160 + 8 = 168.

**Frequently Asked Questions **

### Question 1: How to do addition in vedic maths?

**Answer**: In vedic maths addition is one of the most basic operations. It has certain ways of adding numbers, which is different from traditional methods.

E.g. Addition with base method, addition using balancing rule, etc.

### How to do addition in vedic maths easily?

**Answer**: Certain amount of memorisation is essential, which is the minimum requirement that will vastly improve the efficiency of many calculations.

E.g. 2 + 7 = …., 8 +3 = …., 6 + 8 = ….,

4 + …. = 10, 16 + …. = 20, etc.