** Alternating Current ****MCQ** Chapter 7

**MCQ**Chapter

Below are some of the very important NCERT Alternating Current MCQ Class 12 Physics Chapter 7 with answers. These Alternating Current MCQ have been prepared by expert teachers and subject experts based on the latest syllabus and pattern of CBSE Term 1 examination.

We have given these Alternating Current MCQ Class 12 Physics questions with answers to help students understand the concept.

MCQ Questions for Class 12 Physics are very important for the latest CBSE Term 1 and Term 2 pattern. These MCQs are very important for students who want to score high in CBSE Board, NEET and JEE exam.

We have put together these NCERT Alternating Current MCQ for Class 12 Physics Chapter 7 with answers for the practice on a regular basis to score high in exams. Refer to these MCQs questions with answers here along with a detailed explanation.

**MCQ**

**1. Alternating current cannot be measured by DC ammeter because**

- AC is virtual
- AC changes its direction
- AC cannot pass through DC ammeter
- average value of complete cycle is zero

**2. An alternating current of equivalent value of I _{o}/√2 is**

- RMS current
- DC current
- current
- all of these

**3. In an AC circuit I = 100sin200πt. The time required for current to achieve its peak value will be**

- 1/200 second
- 1/400 second
- 1/100 second
- 1/300 second

**4. The ratio of mean value over half cycle to RMS value of AC is**

- √2:1
- 2:π
- 2√2:π
- √2:π

**5. The peak value of an alternating EMF E given by E = E _{o}cosωt is 10V and its frequency is 50 Hz. At that time t=1/600 s, the instantaneous EMF is**

- 5√3 V
- 5 V
- 10 V
- 1 V

**6. The frequency of an alternating voltage is 50 cps and its amplitude is 120 V. Then the RMS value of voltage is**

- 56.5 V
- 70.7 V
- 101.3 V
- 84.8 V

**7. An electric heater of 40 ohm is connected to a 200V, 50 Hz main supply. The peak value of electric current flowing in the circuit is approximately**

- 10 A
- 5 A
- 7 A
- 2.5 A

**8. In the case of an inductor**

- voltage leads the current by π/4
- voltage leads the current by π/3
- voltage leads the current by π/2
- voltage lacks the current by π/2

**9. A resistance of 20 ohm is connected to a source of an alternating potential V = 220sin(100πt). The time taken by the current to change from its peak value to RMS value is**

- 2.5 x 10
^{-3}s - 25 x 10
^{-3}s - 0.25 s
- 0.2 s

**10. The RMS value of an AC of 50 Hz is 10A. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be**

- 1 x 10
^{-2}s and 7.07 A - 2 x 10
^{-2}s and 14.14 A - 5 x 10
^{-2}s and 14.14 A - 5 x 10
^{-3}s and 7.07 A

**11. Determine The RMS value of the EMF given by**

**E (in V) = 8 sin(ωt) + 6 sin(2ωt)**

- 10√2 V
- 10 V
- 5√2 V
- 7√2 V

**12. An alternating current of frequency f is flowing in a circuit containing a resistor of resistance R and a choke of inductance L in series. The impedance of the circuit is**

- R + 2πfπL
- √(R
^{2}+ L^{2}) - √(R
^{2}+ 2fπL) - √(R
^{2}+ 4π^{2}f^{2}L^{2})

**13. A generator produces a voltage that is given by V = 240 sin 120t V, where t is in seconds. The frequency and RMS voltage and nearly**

- 19 Hz and 120 V
- 19 Hz and 170 V
- 60 Hz and 240 V
- 754 Hz and 170 V

**14. The instantaneous voltage through a device of impedance 20 ohm is e = 80sin100πt. The effective value of the current is **

- 1.732 A
- 2.828 A
- 3 A
- 4 A

**15. A 15μF capacitor is connected to 220V, 50Hz source. Find the capacitive reactance and the RMS current**

- 212.1 Ω; 1.037 A
- 212.1 Ω; 2.037 A
- 412.1 Ω; 1.037 A
- 412.1 Ω; 2.037 A

Click Below To Learn Physics Term 1 Syllabus Chapter-Wise MCQs

Click Below To Learn Chemistry Term-1 Syllabus Chapters MCQs

- Chapter-1: Solid State MCQ
- Chapter-2: Solution MCQ
- Chapter-7: P-Block Element MCQ
- Chapter 10: Haloalkanes and Haloarenes MCQ
- Chapter 11: Alcohols Phenols and Ether MCQ
- Chapter-14: Biomolecules MCQ

**16. In an AC circuit an alternating voltage V = 200√2 sin100t is connected to a capacitor of capacity 1μF. The RMS value of the current in the circuit is**

- 10mA
- 20mA
- 100mA
- 200mA

**17. In an LR circuit, the value of L is (0.4/π) and the value of R is 30Ω. If in the circuit, an alternating EMF of 200V at 50 cps is connected, the impedance of the circuit and current will be**

- 50 Ω, 4 A
- 40.4 Ω, 5 A
- 30.7 Ω, 6.5 A
- 11.4 Ω, 17.5 A

**18. In an AC circuit the voltage applied is E = E _{o}sinωt. The resulting current in the circuit is I = I_{o}sin(ωt – π/2). The power consumption in the circuit is given by**

- P = E
_{o}I_{o}/ 2 - P = E
_{o}I_{o}/ √2 - P = √E
_{o}I_{o} - P = 0

**19. In an LCR circuit AC circuit, the voltage across each of the components L, C and R is 50V. The voltage across the LC combination will be**

- 0 V
- 50 V
- 50√2 V
- 100 V

**20. Find the capacitive reactance of a 10μF capacitor, when it is part of a circuit whose frequency is 100 Hertz.**

- 159.2 Ω
- 412.1 Ω
- 612.1 Ω
- 812.1 Ω

**21. The resonant frequency of a circuit is f. If the capacitance is made 4 times the initial values, than the resonant frequency will become**

- f/2
- f
- 2f
- f/4

**22. A coil of 10Ω and 10mH is connected in parallel to a capacitor of 0.1μF. The impedance of the circuit at resonance is**

- 10
^{3}Ω - 10
^{6}Ω - 10
^{2}Ω - 10
^{4}Ω

**23. Which of the following curves correctly represent the variation of capacitive reactance (X _{c}) with frequency (f)?**

- (a)
- (b)
- (c)
- (d)

**24. How does the current in an RC circuit vary when the charge on the capacitor builds up?**

- it decreases linearly
- it increases linearly
- it decreases exponentially
- it increases exponentially

**25. The impedance in a circuit containing a resistance of 1Ω and an inductance of 0.1 H in series for AC of 50 Hz is**

- √10 Ω
- 10√10 Ω
- 100 Ω
- 100√10 Ω

**26. An AC circuit contains a resistance R, capacitance C and inductance L in series with the source of EMF e=e _{o}sin(ωt+f). The current through the circuit is maximum when**

- ω
^{2}= LC - ωL = 1/ωC
- R = L = C
- ω = LCR

**27. A charged 30μF capacitor is connected to a 27 mH inductor. The angular frequency of free oscillations of the circuit is**

- 1.1 x 10
^{3}rad s^{-1} - 2.1 x 10
^{3}rad s^{-1} - 3.1 x 10
^{3}rad s^{-1} - 4.1 x 10
^{3}rad s^{-1}

**28. The frequency of the output signal becomes ________ times by doubling the value of the capacitance in the LC oscillator circuit.**

- ½
- 2
- √2
- 1/√2

**29. In an LCR circuit, the sharpness of resonance depends on**

- resistance
- capacitance
- inductance
- all of these

**30. The average power dissipation in a pure capacitor in AC circuit is**

- CV
^{2} - 2CV
^{2} - CV
^{2}/2 - zero

**31. In a series resonant circuit, having L, C and R as its elements, the resonant current is ‘i’. The power dissipated in circuit at resonance is**

- Zero
- i
^{2}R - i
^{2}ωL - i
^{2}R/(ωL-(1/ωC))

**32. An AC supply gives 30 V _{RMS} which passes through 10Ω. The power dissipated in it is**

- 45√2 W
- 90√2 W
- 45 W
- 90 W

**33. In a series LCR circuit alternating EMF(e) and current(i) are given by equation v=v _{o}sin(ωt), i=i_{o}sin(wt+π/3). The average power dissipated in the circuit over a cycle of AC is**

- Zero
- v
_{o}i_{o}/2 - v
_{o}i_{o}/4 - (√3/2)v
_{o}i_{o}

**34. In an AC circuit, the current flowing in inductance is I = 5sin(100t-π/2)A and the potential difference V = 200sin(100t)V. The power consumption is equal to**

- Zero
- 20 W
- 40 W
- 1000 W

**35. The power factor in an AC series LR circuit is**

- L/R
- √(R
^{2}+ L^{2}ω^{2}) - R√(R
^{2}+ L^{2}ω^{2}) - R/(√R
^{2}+ L^{2}ω^{2})

**36. A transformer is employed in**

- Convert DC into AC
- Convert AC into DC
- Obtain a suitable DC voltage
- Obtain a suitable AC voltage

**37. The loss of energy in the form of heat in the iron core of a transformer is**

- Copper loss
- Iron loss
- Mechanical loss
- None of these

**38. The core of any transformer is laminated so as to**

- Make it light weight
- Make it robust and strong
- Increase the secondary voltage
- Reduce the energy loss due to eddy currents

**39. A step up transformer has a transformation ratio 5:3. What is the voltage in secondary if voltage in primary is 60 V?**

- 60 V
- 180 V
- 20 V
- 100 V

**40. A transformer has 50 turns in the primary and 100 in the secondary. If the primary is connected to a 220 V DC supply, what will be the voltage across the secondary?**

- 19 V
- 30 V
- 62 V
- 0 V

**41. The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at 1000 V is 12kW, what is the primary voltage?**

- 200 V
- 400 V
- 300 V
- 500 V

**42. A step down transformer is used on a 1000V line to deliver 20A at 120V at the secondary coil. If the efficiency of the transformer is 80% the current drawn from the line is**

- 0.3 A
- 3 A
- 30 A
- 24 A

**43. If the RMS current in a 50 Hz AC circuit is 5 A, the value of the current 1/300 s after its value becomes zero is**

- 5√2 A
- 5√(3/2) A
- ⅚ A
- 5√2 A

**44. An alternating current generator has an internal resistance R _{g} and an internal reactance X_{g}. It is used to supply power to a passive load consisting of a resistance Rg and a reactance X_{L}. For maximum power to be delivered from the generator to the laid, the value of XL is equal to**

- Zero
- X
_{g} - -X
_{g} - R
_{g}

**45. When a voltage measuring device is connected to AC mains, the meter shows the steady input voltage of 220 V. This means**

- Input voltage cannot be AC voltage, but a DC voltage
- Maximum input voltage is 220 V
- The meter reads not v but <v
^{2}> and is calibrated to read √<v^{2}> - The pointer of the meter is stuck by some mechanical defect

**46. To reduce the resonant frequency in an LCR series circuit with a generator**

- The generator frequency should be reduced
- Another capacitor should be added in parallel to the first
- The iron core of the inductor should be removed
- Dielectric in the capacitor should be removed

**47. Which of the following combinations should be selected for better tuning of an LCR circuit used for communication?**

- R = 20Ω, L = 1.5 H, C = 35 μF
- R = 25Ω, L = 2.5 H, C = 45 μF
- R = 15Ω, L = 3.5 H, C = 30 μF
- R = 25Ω, L = 1.5 H, C = 45 μF

**48. An inductor of reactance 1Ω and a resistor of 2Ω are connected in series to the terminals of a 6V(rms) AC source. The power dissipated in the circuit is**

- 8 W
- 12 W
- 14.4 W
- 18 W

**49. The selectivity of a series LCR AC circuit is large when**

- L is large, R is large
- L is small, T is small
- L is large , R is small
- L = R

**50. The phase difference between the current and the voltage in series LCR circuit at resonance is**

- π
- π/2
- π/3
- zero

**MCQ Answers**

1. (4) 2. (1) 3. (2) 4. (3) 5. (1) 6. (4) 7. (3) 8. (3) 9. (1) 10. (3) 11. (3) 12. (4) 13. (2) 14. (2) 15. (1) 16. (2) 17. (1) 18. (4) 19. (1) 20. (1) 21. (1) 22. (4) 23. (2) 24. (3) 25. (2) 26. (2) 27. (1) 28. (4) 29. (4) 30. (4) 31. (2) 32. (4) 33. (3) 34. (1) 35. (4) 36. (4) 37. (2) 38. (4) 39. (4) 40. (4) 41. (1) 42. (2) 43. (2) 44. (3) 45. (3) 46. (2) 47. (3) 48. (3) 49. (3) 50. (4)

**Assertion-Reasoning Based MCQ**

**Code**

- Both assertion and reason are true and reason is the correct explanation of assertion.
- Both assertion and reason are true but reason is not the correct explanation of assertion.
- Assertion is true but reason is false.
- Assertion is false but reason is true.

1. **Assertion** AC is more dangerous in use than DC

**Reason** It is because the peak value of AC is greater than indicated value

2. **Assertion** Average value of AC over a complete cycle is always zero

**Reason** average value of AC is always defined over half cycle

3. **Assertion** The alternating current lags behind the EMF by a phase angle of when AC flows through and inductor

**Reason** The inductive reactance increases as the frequency of AC source decreases

4. **Assertion **Capacitor serves as a block for DC and offers an easy path to AC

**Reason** Capacitive reactance is inversely proportional to frequency

5. **Assertion** In series LCR resonant circuit the impedance is equal to the ohmic resistance

**Reason** At resonance the inductive reactance exceeds the capacitive reactance

6.** Assertion **An alternating current shows magnetic effect

**Reason** Alternating current varies with time

7. **Assertion** In series LCR circuit resonance can take place

**Reason** Resonance takes place in inductance and capacitive reactance are equal and opposite

8. **Assertion** Power factor correction is must in heavy machinery

**Reason** A low power factor implies larger power loss in transmission

9. **Assertion** Choke coil is preferred over a registered to adjust current in an AC circuit

**Reason** Power factor for inductance is zero

10. **Assertion** When AC circuit containing resistor only its power is minimum

**Reason** Power of a circuit is independent of phase angle

11. **Assertion** A transformer cannot work on DC supply

**Reason** DC change is neither in magnitude nor in direction

12. **Assertion** A laminated core is used in transformer to increase eddy currents

**Reason** The efficiency of a transformer increases with increase in eddy currents

13. **Assertion** Soft iron is used as a core of transformer

**Reason **Area of hysteresis loop for soft iron is small

14. **Assertion** An AC generator is based on the phenomenon of electromagnetic induction

**Reason** In single coil we consider self induction only

**Assertion-Reasoning Based MCQ** **Answers**

**1. (1)**

AC is more dangerous in use than DC. It is because the peak value of AC is greater than the indicated value.

2. (2)

The mean or average value of alternating current or EMF during half cycle is given by

I_{m} = 0.636 I_{o}

E_{m} = 0.6363 E_{o}

During the next half cycle, the mean value of AC will be equal in magnitude but opposite in direction. For this reason the average value of AC over a complete cycle is always zero. So the average value is always defined over a half cycle of AC.

**3. (3)**

When AC flows through an inductor current lags behind the EMF, by phase of π/2 inductive reactance

XL = ωL = 2πfL

So, when frequency increases correspondingly inductive reactance also increases.

**4. (1)**

The capacitive reactance of capacitor is given by

XC = 1/ ωC = 1/2πfC

So this is infinite for DC and has a very small value for AC. Hence, a capacitor blocks DC.

**5. (3)**

In series resonance circuit inductive reactance is equal to capacitive reactance.

ωL = 1/ωC

**6. (2)**

Like direct current, an AC also produces magnetic field. But the magnitude and direction of the field goes on changing continuously with time.

**7. (1) **

At resonant frequency,

X_{L} = X_{C}, Z = R (minimum)

**8. (2) **

A heavy machinery requires a large power.

The average power is given by,

P_{av} = E_{rms}I_{rms}cosΦ

The required power can be supplied to the heavy machinery either by supplying larger current or by improving power factor. The first method is costly. Hence, the second one is used.

**9. (1) **

We can use a capacitor of suitable capacitance as a choke coil, because average power consumed per cycle in an ideal capacitor is zero. Therefore, like a choke coil a condenser can reduce AC without power dissipation.

**10. (4)**

The power of an AC circuit is given by,

P = EIcosΦ

Where cosΦ is a power factor and is Φ phase angle. In case of circuit containing resistance only, phase angle is zero and power factor is equal to 1. Therefore power is maximum in case of circuit containing resistor only.

**11. (1)**

Transformer works on AC only AC changes in magnitude as well as in direction and induced EMF.

**12. (4)**

Large eddy currents are produced in non laminated iron core of the transformer by induced EMF, as the resistance of bulk iron core is very small. By using thin iron sheets are score the resistance is increased. Laminating the core substantially reduces the eddy currents. Eddy currents heat up the core of the transformer. More the eddy current greater the loss of energy and efficiency goes down.

**13. (1) **

Hysteresis loss in the core of transformer is directly proportional to the hysteresis loop area of the core material. Since soft iron has narrow hysteresis loop area, that is why soft iron core is used in transformer.

**14. (2)**

According to electromagnetic induction, whenever the magnetic flux changes and EMF will be induced in the coil.

Click Below To Learn Physics Term 1 Syllabus Chapter-Wise MCQs

**Case-Study Based MCQ**

**1. The figure shows a series LCR circuit.**

**For such a citcuit, the impedance Z is given by Z = √R ^{2} + (X_{L} – X_{C})^{2} where X_{L} and X_{C} are inductive and capacitive resistances respectively. As the frequency of AC is increased, at a particular frequency, X_{L} becomes equal to X_{C}. For that frequency, maximum current occurs. This is because the impedcane becomes equal to the least value which is R. **

**Current through the circuit is I = V/R. This circuit behaves like a pure resistive circuit and current and voltage will be in phase. This is called resonance. Frequency of AC at which resonance occurs is called resonant frequency. If frequency is less than the resonant frequency, then the capacitive reactance will be more. The circuit will be capacitive in nature.**

**If frequency is more than the resonant frequency, inductive reactance will be more. Circuit is inductive in nature and the current lags behind the voltage by a phase of π/2.**

**An LCR circuit which has a resistance 50 ohm has a resonant angular frequency 2 x 10 ^{3} rad/s. At resonance, the voltage across the resistance and inductance are 25 V and 20 V respectively.**

(i) The value of inductance is

(a) 20mH

(b) 10mH

(c) 40mH

(d) 25mH

(ii) The value of capacitive reactance is

(a) 25μF

(b) 1μF

(c) 2μF

(d) 12.5 μF

(iii) The impedance at resonance is

(a) 50 ohm

(b) 16 ohm

(c) 64 ohm

(d) 25 ohm

(iv) Which of the following angular frequency of AC will see the circuit as inductive in nature?

(a) 1.5 x 10^{3} rad/s

(b) 10^{3} rad/s

(c) 2 x 10^{3} rad/s

(d) 5 x 10^{3} rad/s

(v) At angular frequency 10^{3} rad/s, the nature of circuit is

(a) inductive

(b) capacitive

(c) resisitive

(d) none of these

**2. A series LCR circuit consist of series combination of a resistance, an inductor and a capacitance. A similar series LCR circuit is shown in figure. The given series LCR circuit is connected across a 200 V 60 Hz line consisting of capacitive reactance 30 ohm a non-inductive resistor of 44 ohm and a coil of inductive reactance 90 ohm and resistance 36 ohm.**

(i) Calculate the total impedance of the circuit.

(a) 1000 ohm

(b) 100 ohm

(c) 3600 ohm

(d) 4900 ohm

(ii) Calculate the current flowing in the circuit.

(a) 1 A

(b) 5 A

(c) 2 A

(d) 10 A

(iii) What is the impedance of the coil?

(a) 97 ohm

(b) 87 ohm

(c) 100 ohm

(d) 110 ohm

(iv) what is the potential difference across the coil?

(a) 194 V

(b) 186 V

(c) 180 V

(d) 190 V

(v) Calculate the power dissipated in the coil.

(a) 100 W

(b) 122 W

(c) 130 W

(d) 144 W

**Case-Study Based MCQ** **Answers**

1. (i) (a) XL = VL/I

I = V_{R}/R = 25/50 = 1/2

X_{L} = 20/(1/2) = 40 ohm

X_{L} = ωL ; L = 40 / (2 x 10^{3}) = 20 x 10^{-3} = 20mH

(ii) (d) ω^{2} = 1/LC ; C = 1/( ω^{2}L) = 1 / ((2 x 10^{3})^{2} x 20 x 10^{-3}) = 12.5 μF

(iii) (a) At resonance, the impedance equal just resistance.

(iv) (d) For inductive nature, ω > ω_{r}

(v) (b) If ω < ω_{r}, the circuit will be capacitive in nature.

2. (i) (b) Z = √((R_{1} + R_{2})^{2} + (X_{L} – X_{C})^{2}) = √((44 + 36)^{2} + (90 – 30)^{2}) = 100 ohm

(ii) (c) Current, I = V/Z = 200/100 = 2A

(iii) (a) Impedance of the coil, Z_{L} = √(R_{2}^{2} + X_{L}^{2}) = √((36)^{2} + (90)^{2}) = 97 ohm

(iv) (a) Potential difference across the coil, V_{L} = IZ_{L} = 2 x 97 = 194 V

(v) (d) Power dissipated in the inductive coil, P = I^{2}R_{2} = (2)^{2} x 36 = 144 W

Click Below To Learn Physics Term 1 Syllabus Chapter-Wise MCQs

Click Below To Learn Chemistry Term-1 Syllabus Chapters MCQs

- Chapter-1: Solid State MCQ
- Chapter-2: Solution MCQ
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- Chapter 10: Haloalkanes and Haloarenes MCQ
- Chapter 11: Alcohols Phenols and Ether MCQ
- Chapter-14: Biomolecules MCQ

**Final Words**

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